Answer
$$r=-\frac{hv^2}{v^2-2gh}$$
Work Step by Step
Solving the equation for $r$ using the rules of Algebra, we obtain:
$$ v^2=\left(\sqrt{2gr}\sqrt{\frac{h}{r+h}}\right)^2\\ v^2=\frac{2ghr}{r+h}\\ r=-\frac{hv^2}{v^2-2gh}$$
Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)
by Bittinger, Marvin L.; Ellenbogen, David J.; Johnson, Barbara L.
Published by
Pearson
ISBN 10:
0-32184-874-8
ISBN 13:
978-0-32184-874-1
Chapter 10 - Exponents and Radicals - 10.6 Solving Radical Equations - 10.6 Exercise Set - Page 669: 73
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