Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 10 - Exponents and Radicals - 10.6 Solving Radical Equations - 10.6 Exercise Set - Page 669: 73



Work Step by Step

Solving the equation for $r$ using the rules of Algebra, we obtain: $$ v^2=\left(\sqrt{2gr}\sqrt{\frac{h}{r+h}}\right)^2\\ v^2=\frac{2ghr}{r+h}\\ r=-\frac{hv^2}{v^2-2gh}$$
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