# Chapter 10 - Exponents and Radicals - 10.6 Solving Radical Equations - 10.6 Exercise Set - Page 669: 72

$$h=\frac{v^2r}{2gr-v^2}$$

#### Work Step by Step

Solving the equation for $h$ using the rules of Algebra, we obtain: $$\sqrt{\frac{h}{r+h}}=\frac{\sqrt{2}v\sqrt{gr}}{2gr}\\ \frac{h}{r+h}=\frac{v^2}{2gr}\\ h=\frac{v^2r}{2gr-v^2}$$

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