Answer
$$h=\frac{v^2r}{2gr-v^2}$$
Work Step by Step
Solving the equation for $h$ using the rules of Algebra, we obtain:
$$ \sqrt{\frac{h}{r+h}}=\frac{\sqrt{2}v\sqrt{gr}}{2gr}\\ \frac{h}{r+h}=\frac{v^2}{2gr}\\ h=\frac{v^2r}{2gr-v^2}$$
Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)
by Bittinger, Marvin L.; Ellenbogen, David J.; Johnson, Barbara L.
Published by
Pearson
ISBN 10:
0-32184-874-8
ISBN 13:
978-0-32184-874-1
Chapter 10 - Exponents and Radicals - 10.6 Solving Radical Equations - 10.6 Exercise Set - Page 669: 72
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