Answer
9
Work Step by Step
We are asked to evaluate the given equation for $c=14$ and $d=13$. We can plug in directly to evaluate.
$\frac{c+d}{3}=\frac{(14)+(13)}{3}=\frac{27}{3}=\frac{27\div3}{3\div3}=\frac{9}{1}=9$
Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)
by Bittinger, Marvin L.; Ellenbogen, David J.; Johnson, Barbara L.
Published by
Pearson
ISBN 10:
0-32184-874-8
ISBN 13:
978-0-32184-874-1
Chapter 1 - Introduction to Algebraic Expressions - 1.1 Introduction to Algebra - 1.1 Exercise Set - Page 8: 18
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