Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 1 - Introduction to Algebraic Expressions - 1.1 Introduction to Algebra - 1.1 Exercise Set: 18

Answer

9

Work Step by Step

We are asked to evaluate the given equation for $c=14$ and $d=13$. We can plug in directly to evaluate. $\frac{c+d}{3}=\frac{(14)+(13)}{3}=\frac{27}{3}=\frac{27\div3}{3\div3}=\frac{9}{1}=9$
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