## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Evaluate $\frac{a+b}{4}$ where a is twice b and a is 16. Given the value of a, solve for b. $a=2b\longrightarrow$ Substitute the value for a. $16=2b\longrightarrow$ Divide both sides by 2. $16\div2=2b\div2\longrightarrow$ Solve. $8=b$ Substitute for a and b in the original equation and solve. $\frac{a+b}{4}=\frac{16+8}{4}=\frac{24}{4}=6$