Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 1 - Introduction to Algebraic Expressions - 1.1 Introduction to Algebra - 1.1 Exercise Set - Page 11: 82


$158.75\ cm^2$

Work Step by Step

To find the area of the shaded part of the figure, first find the area of the complete rectangle then subtract the area of the triangle that is not shaded. The area of the rectangle is $bh=(20\ cm)(10\ cm)=200\ cm^2$ The length of the base of the triangle is not given, but can be found by subtracting the portions of the base of the rectangle that are not part of the triangle. The area of the triangle is $\frac{1}{2}bh=\frac{1}{2}(20-4-5\ cm)(7.5\ cm)=\frac{1}{2}(11\ cm)(7.5\ cm)=41.25\ cm^2$ Subtract the area of the triangle from the area of the rectangle to find the shaded area. $200\ cm^2-41.25\ cm^2=158.75\ cm^2$
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