Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 1-8 - Cumulative Review - Page 574: 25



Work Step by Step

We know that this expression is the same as: $$ g(a)-h(a)$$ Thus, we find: $$ 4a-3-\left(-2a^2+1\right)\\ 4a-3+2a^2-1\\ 2a^2+4a-4$$
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