Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 1-8 - Cumulative Review - Page 574: 13


$$ y=\frac{2}{5},\:x=-3$$

Work Step by Step

Solving the system of equations using substitution, we find: $$ -11\cdot \frac{-11+5y}{3}-15y=27\\ y=\frac{2}{5}\\ x=\frac{-11+5\cdot \frac{2}{5}}{3}\\ x=-3$$
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