Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 1-7 - Cumulative Review - Page 500: 26

Answer

$$a=-\frac{bP}{P-4};\quad \:P\ne \:4$$

Work Step by Step

We solve the problem by isolating the variable. Doing this, we find: $$ P\left(a+b\right)=4a \\ aP-4a=-bP\\ a\left(P-4\right)=-bP\\ a=-\frac{bP}{P-4};\quad \:P\ne \:4$$
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