Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 1-7 - Cumulative Review - Page 500: 25

Answer

$$x=-1$$

Work Step by Step

We solve the problem by using cross multiplication and then isolating the variable. Doing this, we find: $$ \frac{6}{x-5}=\frac{1}{x}\\ 6x=\left(x-5\right)\cdot \:1\\ 5x=-5 \\ x=-1$$
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