## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$$x=-1$$
We solve the problem by using cross multiplication and then isolating the variable. Doing this, we find: $$\frac{6}{x-5}=\frac{1}{x}\\ 6x=\left(x-5\right)\cdot \:1\\ 5x=-5 \\ x=-1$$