Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 9 - Roots and Radicals - 9.2 - Simplifying Radicals - Concept Quiz 9.2 - Page 406: 9

Answer

False

Work Step by Step

Checking if the statement is true or false by simplifying the expression ourselves, we obtain: $\sqrt {8x^{3}y^{2}}$ =$\sqrt 8\times \sqrt {x^{3}}\times\sqrt {y^{2}}$ =$\sqrt {4\times2}\times \sqrt {x^{2}\times x}\times\sqrt {y^{2}}$ =$\sqrt {2^{2}\times2}\times \sqrt {x^{2}\times x}\times\sqrt {y^{2}}$ =$2\sqrt {2}\times x\sqrt {x}\times y$ =$2\times x\times y \times\sqrt 2\times\sqrt x$ =$2\times x\times y \times\sqrt {2\times x}$ =$2xy \times\sqrt {2x}$ =$2xy\sqrt {2x}$ Therefore, $\sqrt {8x^{3}y^{2}}=2xy\sqrt {2x}$.
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