Answer
False
Work Step by Step
Checking if the statement is true or false by simplifying the expression ourselves, we obtain:
$\sqrt {121x^{2}y^{4}}$
=$\sqrt {121}\times \sqrt {x^{2}}\times\sqrt {y^{4}}$
=$\sqrt {11^{2}}\times \sqrt {x^{2}}\times\sqrt {y^{4}}$
=$11 \times x \times y^{2}$
=$11xy^{2}$
Therefore, $\sqrt {121x^{2}y^{4}}=11xy^{2}$. Thus, the original statement is false.
