## Elementary Algebra

Checking if the statement is true or false by simplifying the expression ourselves, we obtain: $\sqrt {121x^{2}y^{4}}$ =$\sqrt {121}\times \sqrt {x^{2}}\times\sqrt {y^{4}}$ =$\sqrt {11^{2}}\times \sqrt {x^{2}}\times\sqrt {y^{4}}$ =$11 \times x \times y^{2}$ =$11xy^{2}$ Therefore, $\sqrt {121x^{2}y^{4}}=11xy^{2}$. Thus, the original statement is false.