Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 7 - Algebraic Fractions - Chapter 7 Review Problem Set - Page 322: 2


$= \frac{x}{(x+3)}$

Work Step by Step

$\frac{x^{2}-9x}{x^{2}-6x-27}$ 1. Factor the numerator: $= \frac{x(x-9)}{x^{2}-6x-27}$ 2. Factor the denominator: $= \frac{x(x-9)}{(x-9)(x+3)}$ 3. Cancel out $x-9$ as both the numerator and denominator contains that component: $= \frac{x}{(x+3)}$
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