Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 7 - Algebraic Fractions - Chapter 7 Review Problem Set: 1

Answer

$= \frac{7x^{2}}{9y^{2}}$

Work Step by Step

1. Simplify $\frac{56}{72}$ $= \frac{28}{36}$ $= \frac{14}{18}$ $= \frac{7}{9}$ 2. Simplify $\frac{x^{3}y}{xy^{3}}$ a) Cancel out $x$ from the numerator and denominator. This leaves you with $x^{2}$ in the numerator and $1$ in the denominator. b) Cancel out $y$ from the numerator and denominator. This leaves you with $1$ in the numerator and $y^{2}$ in the denominator. $= \frac{x^{2}y}{1y^{3}}$ $= \frac{x^{2}(1)}{1y^{2}}$ $= \frac{x^{2}}{y^{2}}$ 3. Multiply the components in Step #1 and #2 together: $= \frac{7}{9}(\frac{x^{2}}{y^{2}})$ $= \frac{7x^{2}}{9y^{2}}$
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