## Elementary Algebra

In order to solve each of the equations, we first factor the equation. Then, we set each factor equal to zero in order to solve: a) $(n+12)(n+18) \\ n =-12, -18$ b) $(n+21)(n+14) \\ n =-21, -14$ c) $(n-16)(n-24) \\ n =16, 24$ d) $(n-15)(n-25) \\ n =15, 25$ e) $(n-18)(n+24) \\ n =18, -24$ f) $(n+16)(n-32) \\ n =-16,32$