## Elementary Algebra

Let s be the side of the square. Thus: $s^2 + lw =64$ Since l =s+4 and w = s+2, we find: $s^2 + (s+2)(s+4) = 64 \\ 2s^2 + 6s +-56 = 0 \\ 2(s-4)(s+7)=0$ Since s cannot be negative, we find: $s=4$ Thus, the square is 4 by 4, and the rectangle is 4+2 by 4+4, which is 6 by 8.