## Elementary Algebra

$\frac{24x^{6}-18x^{4} +12x^{2}}{2x^{2}}$ = 12$x^{4}$ - 9$x^{2}$ + 6 To check if this is true or not, we simplify the left side. RECALL: $\frac{b^{n}}{b^{m}}$ = $b^{n-m}$ So, $\frac{24x^{6}-18x^{4} +12x^{2}}{2x^{2}}$ = $\frac{24x^{6}}{2x^{2}}$ - $\frac{18x^{4}}{2x^{2}}$ + $\frac{12x^{2}}{2x^{2}}$ = $\frac{24}{2}$$x^{6-2} - \frac{18}{2}$$x^{4-2}$ + $\frac{12}{2}$$x^{2-2}$ = 12$x^{4}$ - 9$x^{2}$ + 6 Because 12$x^{4}$ - 9$x^{2}$ + 6 is equal to 12$x^{4}$ - 9$x^{2}$ + 6, this statement is true.