Answer
True
Work Step by Step
$\frac{-30x^{5}+20x^{4} -10x^{3}}{-5x^{2}}$ = 6$x^{3}$ - 4$x^{2}$ + 2x
To check if this is true or not, we simplify the left side.
RECALL:
$\frac{b^{n}}{b^{m}}$ = $b^{n-m}$
So, $\frac{-30x^{5}+20x^{4} -10x^{3}}{-5x^{2}}$ =
$\frac{-30x^{5}}{-5x^{2}}$ + $\frac{20x^{4}}{-5x^{2}}$ + $\frac{-10x^{3}}{-5x^{2}}$ = $\frac{-30}{-5}$$x^{5-2}$ + $\frac{20}{-5}$$x^{4-2}$ + $\frac{-10}{-5}$$x^{3-2}$ =
6$x^{3}$ - 4$x^{2}$ + 2x
Because 6$x^{3}$ - 4$x^{2}$ + 2x is equal to 6$x^{3}$ - 4$x^{2}$ + 2x, this statement is true.