## Elementary Algebra

Published by Cengage Learning

# Chapter 5 - Exponents and Polynomials - 5.3 - Multiplying Polynomials - Problem Set 5.3: 131

#### Answer

The answers are below.

#### Work Step by Step

In order to do this, multiply each first digit of each number by itself plus one. Then, multiply the result by 100, and add 25: a) $(1)(2)(100) + 25 = 225$ b) $(2)(3)(100) + 25 = 625$ c) $(4)(5)(100) + 25 = 2025$ ' d) $(5)(6)(100) + 25 = 3025$ e) $(6)(7)(100) + 25 = 4225$ f) $(7)(8)(100) + 25 = 5625$ g) $(8)(9)(100) + 25 = 7225$ h) $(9)(10)(100) + 25 = 9025$ i) $(10)(11)(100) + 25 = 11025$

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