Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 5 - Exponents and Polynomials - 5.2 - Multiplying Monomials - Problem Set 5.2: 78

Answer

$-a^{10}b^{11}c^{12}$

Work Step by Step

Using the laws of exponents, the given expression, $ (ab^2c^3)^4(-a^2b)^3 ,$ simplifies to \begin{array}{l}\require{cancel} a^{1(4)}b^{2(4)}c^{3(4)}\cdot (-1)^3a^{2(3)}b^{1(3)} \\\\= a^{4}b^{8}c^{12}\cdot (-1)a^{6}b^{3} \\\\= (-1)a^{4+6}b^{8+3}c^{12} \\\\= -a^{10}b^{11}c^{12} .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.