Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 5 - Exponents and Polynomials - 5.2 - Multiplying Monomials - Problem Set 5.2: 77

Answer

$-a^{12}b^{5}c^{9}$

Work Step by Step

Using the laws of exponents, the given expression, $ (-a^2bc^3)^3(a^3b)^2 ,$ simplifies to \begin{array}{l}\require{cancel} (-1)^3a^{2(3)}b^{1(3)}c^{3(3)}\cdot a^{3(2)}b^{1(2)} \\\\= (-1)a^{6}b^{3}c^{9}\cdot a^{6}b^{2} \\\\= (-1)a^{6+6}b^{3+2}c^{9} \\\\= -a^{12}b^{5}c^{9} .\end{array}
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