Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 4 - Proportions, Percents, and Solving Inequalities - Chapter 4 Test - Page 185: 7



Work Step by Step

Multiplying both sides by the $LCD= 24 $ and then using the properties of equality, the value of the variable that satisfies the given equation, $ \dfrac{h}{4}+\dfrac{h}{6}=1 ,$ is \begin{array}{l}\require{cancel} 6(h)+4(h)=24(1) \\\\ 6h+4h=24 \\\\ 10h=24 \\\\ h=\dfrac{24}{10} \\\\ h=\dfrac{\cancel{2}\cdot12}{\cancel{2}\cdot5} \\\\ h=\dfrac{12}{5} .\end{array}
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