Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 4 - Proportions, Percents, and Solving Inequalities - 4.1 - Ratios and Proportions - Problem Set 4.1: 80

Answer

This equation is true for every value of x except 0.

Work Step by Step

Because x is in the denominator, and the denominator cannot equal 0, x $\ne$ 0. We must multiply both sides of the equation by x. x + 3 = (1 + $\frac{3}{x}$) $\times$ x Use the distributive property. x + 3 = x + 3 Subtract x from both sides. 3 = 3 As we can see, this equation is true for every value of x, except the case when x = 0, because we found out at the beginning that x $\ne$ 0.
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