Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 4 - Proportions, Percents, and Solving Inequalities - 4.1 - Ratios and Proportions - Problem Set 4.1: 78

Answer

There is no value of x that can make this equation true.

Work Step by Step

Because x - 1 is in the denominator, and the denominator cannot equal 0, x - 1 $\ne$ 0. x $\ne$ 1 To solve this equation, we equate the cross products. 6 $\times$ (x - 1) = 5 $\times$ (x - 1) 6x - 6 = 5x - 5 Subtract 5x from both sides. x - 6 = -5 Add 6 to both sides. x = 1 However, at the beginning, we stated that x $\ne$ 1. So, there is no value of X that can make this equation true.
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