## Elementary Algebra

Because x - 1 is in the denominator, and the denominator cannot equal 0, x - 1 $\ne$ 0. x $\ne$ 1 To solve this equation, we equate the cross products. 6 $\times$ (x - 1) = 5 $\times$ (x - 1) 6x - 6 = 5x - 5 Subtract 5x from both sides. x - 6 = -5 Add 6 to both sides. x = 1 However, at the beginning, we stated that x $\ne$ 1. So, there is no value of X that can make this equation true.