Elementary Algebra

$-55, -56, and -57$
The sum of 3 consecutive integers is $(x-1)+(x)+(x+1) = -168$ Adding the 3 together gives $3x = -168$ Divide both sides by 3 to obtain: $x = \frac {-168}{3} = -56$ Substitute the value for $x$ into $x+1$ and $x-1$, we find that the value of the three integers are $-55, -56, and -57$