Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 3 - Equations and Problem Solving - Chapter 3 Test - Page 139: 11



Work Step by Step

Using the properties of equality, in terms of $ C ,$ the given equation, $ F=\dfrac{9C+160}{5} ,$ is equivalent to \begin{array}{l}\require{cancel} 5F=9C+160 \\\\ 5F-160=9C \\\\ \dfrac{5F-160}{9}=C \\\\ C=\dfrac{5F-160}{9} .\end{array}
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