## Elementary Algebra

$C=\dfrac{5F-160}{9}$
Using the properties of equality, in terms of $C ,$ the given equation, $F=\dfrac{9C+160}{5} ,$ is equivalent to \begin{array}{l}\require{cancel} 5F=9C+160 \\\\ 5F-160=9C \\\\ \dfrac{5F-160}{9}=C \\\\ C=\dfrac{5F-160}{9} .\end{array}