Chapter 2 - Real Numbers - 2.3 - Real Numbers and Algebraic Expressions - Problem Set 2.3 - Page 69: 78

-14.9

Work Step by Step

We evaluate the expression by substituting the values of $x=5$ and $y=-9$ into the expression, $0.8x+2.1y$ =$0.8(5)+2.1(-9)$ =$\frac{8}{10}(5)+\frac{21}{10}(-9)$ =$\frac{40}{10}-\frac{189}{10}$ =$\frac{40-189}{10}$ =$\frac{-149}{10}$ =$-14.9$

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