Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 2 - Real Numbers - 2.3 - Real Numbers and Algebraic Expressions - Problem Set 2.3 - Page 69: 76



Work Step by Step

To evaluate the expression, we substitute the values $x=-4.3$ and $y=5.2$ into the expression: $8x-9y$ =$8(-4.3)-9(5.2)$ =$8(-\frac{43}{10})-9(\frac{52}{10})$ =$(-\frac{344}{10})-(\frac{468}{10})$ =$\frac{-344-468}{10}$ =$\frac{-812}{10}$ =$-81.2$
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