Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 2 - Real Numbers - 2.3 - Real Numbers and Algebraic Expressions - Problem Set 2.3: 33

Answer

$0.0156$

Work Step by Step

The product of a negative real number and a negative real number is a positive real number. We convert the decimal into a fraction for the ease of simplification: $(-0.12)(-0.13)$ =$-\frac{12}{100}\times-\frac{13}{100}$ =$\frac{-12\times-13}{100\times100}$ =$\frac{156}{10000}$ =$0.0156$
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