Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 2 - Real Numbers - 2.1 - Rational Numbers: Multiplication and Division - Problem Set 2.1 - Page 49: 73

Answer

$\frac{20}{9}$

Work Step by Step

$\frac{5}{2}$ $\times$ $\frac{2}{3}$ $\div$ (-$\frac{1}{4}$) $\div$ (-3) RECALL: $\frac{a}{b}$ $\div$ $\frac{c}{d}$ = $\frac{a}{b}$ $\times$ $\frac{d}{c}$ Use the rule above to obtain: $\frac{5}{2}$ $\times$ $\frac{2}{3}$ $\times$ (-$\frac{4}{1}$) $\times$ (-$\frac{1}{3}$) Multiply the numerators by each other, and multiply the denominators by each other: $\frac{5\ \times\ 2\ \times\ (-4)\ \times\ (-1)}{2\ \times\ 3\ \times\ 1\ \times\ 3}$ = Factor the numerator and the denominator: $\frac{5\ \times\ 2\ \times\ (-1)\ \times\ 2\ \times\ 2\ \times\ (-1)}{2\ \times\ 3\ \times\ 1\ \times\ 3}$ = Cancel the common factors in the numerator and the denominator to obtain: $\frac{5\ \times\ 2\ \times\ 2 \times -1 \times -1}{3\ \times\ 3}$ = $\frac{20}{9}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.