Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 11 - Additional Topics - 11.5 - Quadratic Equations: Complex Solutions - Problem Set 11.5 - Page 496: 11



Work Step by Step

Using the rules of factoring trinomials to factor, we obtain: $a^{2}-3a-4=0$ $a^{2}+1a-4a-4=0$ $a(a+1)-4(a+1)=0$ $(a+1)(a-4)=0$ $(a+1)=0$ or $(a-4)=0$ $a=-1$ or $a=4$ Therefore, the solution set is {$-1,4$}.
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