Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 11 - Additional Topics - 11.5 - Quadratic Equations: Complex Solutions - Problem Set 11.5: 10



Work Step by Step

We know that if $x^{2}=a$, then $x=\pm \sqrt{a}$. Thus, we obtain: Step 1: $(7x+3)^{2}=1$ Step 2: $7x+3=\pm \sqrt {1}$ Step 3: $7x+3=\pm 1$ Step 4: $7x=-3\pm 1$ Step 5: $x=\frac{-3\pm 1}{7}$ Step 6: $x=\frac{-3+ 1}{7}$ or $x=\frac{-3-1}{7}$ Step 7: $x=\frac{-2}{7}$ or $x=\frac{-4}{7}$ Therefore, the solution set is {$-\frac{2}{7},-\frac{4}{7}$}.
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