## Elementary Algebra

Published by Cengage Learning

# Chapter 10 - Quadratic Equations - Chapter 10 Review Problem Set - Page 468: 31

#### Answer

$6\sqrt{2}$

#### Work Step by Step

Regardless of whether or not it is a right triangle, the legs of an isosceles triangle are $\frac{\sqrt{2}}{2}$ as long as the hypotenuse. Thus: $l = 12 \times \frac{\sqrt{2}}{2} = 6\sqrt{2}$

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