#### Answer

Two possibilities:
Jay went 45 mph and Jean went 48 mph
OR
Jay went 7.5 mph and Jean went 10.5 mph

#### Work Step by Step

Recall that velocity is equal to change in distance over change in time. We call t the time it takes Jay. Thus, we obtain:
$\frac{336}{t+2} = \frac{225}{t} + 3 $
We create common denominators and solve for t:
$ \frac{336t}{t(t+2)} = \frac{225(t+2)}{t(t+2)} + \frac{3t(t+2)}{t(t+2)}$
Since the denominators are the same, we cancel them out and solve. (Recall, t cannot be negative.)
$ 0 = (t-30)(t-5)$
Since both values yield positive results, we must consider both:
$ v_{Jay} = 225 / 30 = 7.5 $
$ v_{Jean} = 7.5 + 3 = 10.5$
OR
$v_{Jay} = 225/5 = 45$
$ v_{Jean} = 45 + 3 = 48$