Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 10 - Quadratic Equations - 10.5 - Solving Problems Using Quadratic Equations - Problem Set 10.5 - Page 463: 26

Answer

It was 11 by 14 inches

Work Step by Step

We know: $ l = w+3$ Since 2 inch squares are cut off each side, we know that the length and width of the cube are each 4 less than the length and width of the rectangle, and we know that the cube's height is 2. (Recall, width can't be negative.) Thus: $ V = lwh \\ 140 = (w+3)(w)(2) \\ 0 = 2w^2 +6w - 140 \\ (2)(w-7)(w+10) \\ w =7 $ Since the width of the original cardboard is 4 inches longer, its width is 11 inches. This means that the original length is 11 +3 = 14 inches.
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