#### Answer

It was 7 by 9 originally.

#### Work Step by Step

We first set up the equations:
$ lw = 63$
And
$ 3l + 3w + 9 = 57 $
Using $ l = 63/w $ from the first equation, we find:
$ 3(63)/w + 3w = 48 \\ \frac{189}{w} + 3w = 48 \\ \frac{189}{w} + \frac{3w^2}{w} = \frac{48w}{w} \\ 3w^2 -48w + 189 = 0 \\ (w-9)(w-7)$
The smaller value is width, and the longer value is length, so we obtain that it is a 7 by 9 rectangle.