## Elementary Algebra

We solve the equation using the square root property: $(3x+4)^{2}=64$ $\sqrt {(3x+4)^{2}}=\sqrt {64}$ $3x+4=\pm 8$ $3x+4=8$ or $3x+4=-8$ $3x=4$ or $3x=-12$ $x=\frac{4}{3}$ or $x=-4$ Therefore, the solution set of the equation is {$-4,\frac{4}{3}$}. Since both of these numbers are rational, the statement of the question is true.