## Elementary Algebra

We solve the equation using the square root property: $(x-6)^{2}=0$ $\sqrt {(x-6)^{2}}=\sqrt 0$ $x-6=\pm 0$ $x-6=0$ or $x-6=0$ $x=6$ or $x=6$ Therefore, the solution set of the equation is {$6$}. It can be seen that the solution set consists of only one integer, and as a result, the statement of the question is false.