Differential Equations and Linear Algebra (4th Edition)

Published by Pearson
ISBN 10: 0-32196-467-5
ISBN 13: 978-0-32196-467-0

Chapter 8 - Linear Differential Equations of Order n - 8.4 Complex-Valued Trial Solutions - Problems - Page 529: 10

Answer

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Work Step by Step

$y''-2y'+10y=24e^{x}\cos 3x$ The complementary function is $y_c(x)=c_1 e^{x}\sin 3x+c_2 e^{x} \cos 3x$ We consider the complex differential equation $z''-2z'+10z=24e^{(1+3i)x}$ An appropriate complex-valued trial solution for this differential equation is: $z_p(x)=A_0xe^{(-1+2i)x}$ where $A_0$ is a complex constant. so that $z _p$ is a solution if and only if $6iA_0e^{(1+3i)x}=24e^{(1+3i)x}\\ \rightarrow A_0=-4i$ Hence, $z=-4ixe^{(1+3i)x}$ A particular solution is: $y_p(x)=Re_{\{z_p\}}=4xe^{x}\sin 3x$ so that the general solution is $y(x)=c_1e^{x}\sin 3x+c_2e^{x}\cos 3x + 4xe^{x}\sin 3x$
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