Answer
$y (x)= (\sin x+\cos x) \in ker (L)$
Work Step by Step
We have: $Ly=(D^3+D^2+D+1)(\sin x+\cos x)$
$L(\sin x+\cos x)=(-\cos x+\sin x)+(-\sin x-\cos x)+(\cos x -\sin x)+(\cos x -\sin x)\\=-\cos x+\sin x -\sin x -\cos x+\cos x-\sin x+\cos x +\sin x \\=0$
This yields $y (x)= (\sin x+\cos x) \in ker (L)$