Answer
False
Work Step by Step
Assume $p(x)=0+0x+0x^2$
Obtain $
=0$ Since $p(x) \ne 0 + 0x+0x^2$, $<>$ is not an inner product on $P_2$. We can not define an inner product on $P_2(R)$ via $
=a_0b_0$
Differential Equations and Linear Algebra (4th Edition)
by Goode, Stephen W.; Annin, Scott A.
Published by
Pearson
ISBN 10:
0-32196-467-5
ISBN 13:
978-0-32196-467-0
Chapter 5 - Inner Product Spaces - 5.1 Definition of an Inner Product Space - True-False Review - Page 350: g
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