Answer
False
Work Step by Step
Given any $u, v \in V$ and $k \in R$, we have that
\begin{align}
\langle k \ u,k\ v\rangle&=k\langle \ u,k\ v\rangle\\
&=k \overline{\langle k \ v,u\rangle}\\
&=k \overline{k}\ \overline{\langle \ v,u\rangle}\\
&=k \overline{k}\ \langle \ u,v\rangle\\
& =|k|^{2}\langle \ u,v\rangle\\
\end{align}
So, the statement is false