Answer
See answers below
Work Step by Step
Assume $V$ be an inner product space.
From exercise 35, we have:
$$||v+w||^2=||v||^2+2(v,w)+||w||^2$$
Thus:
$||v-w||^2=||v||^2-2(v,w)+||w||^2$
then
$$||v+w||^2-||v-w||^2=||v||^2+2(v,w)+||w||^2-(||v||^2-2(v,w)+||w||^2))\\
=4(v,w)$$
$$||v+w||^2+||v-w||^2=||v||^2+2(v,w)+||w||^2+(||v||^2-2(v,w)+||w||^2))\\
=2(||v||^2+||w||^2)$$