Differential Equations and Linear Algebra (4th Edition)

Published by Pearson
ISBN 10: 0-32196-467-5
ISBN 13: 978-0-32196-467-0

Chapter 5 - Inner Product Spaces - 5.1 Definition of an Inner Product Space - Problems - Page 352: 36

Answer

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Work Step by Step

Assume $V$ be an inner product space. From exercise 35, we have: $$||v+w||^2=||v||^2+2(v,w)+||w||^2$$ Thus: $||v-w||^2=||v||^2-2(v,w)+||w||^2$ then $$||v+w||^2-||v-w||^2=||v||^2+2(v,w)+||w||^2-(||v||^2-2(v,w)+||w||^2))\\ =4(v,w)$$ $$||v+w||^2+||v-w||^2=||v||^2+2(v,w)+||w||^2+(||v||^2-2(v,w)+||w||^2))\\ =2(||v||^2+||w||^2)$$
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