Answer
See answers below
Work Step by Step
Assume $V$ be an inner product space.
Since $v,w \in V$ we have
a)
$$||v+w||^2\\
=(\sqrt (v+w,v+w)^2\\
=(v,v)+(v,w)+(w,v)+(w,w)\\
=||v||^2+2(v,w)+||w||^2$$
b) Since $v,w \in V \rightarrow (v,w)=0$
then $$||v+w||^2=||v||^2+2(v,w)+||w||^2\\
=||v||^2+||w||^2$$