Answer
See below
Work Step by Step
Let $\{v_1, v_2,..., v_k\}$ be a set of at least two vectors in a vector space $V$. If one of the vectors in the set is a linear combination of the other vectors in the set, then that vector can be deleted from the given set of vectors and the linear span of the resulting set of vectors will be the same as the linear span of $\{v_1, v_2,..., v_k\}$
Let $V=R^3$
Suppose $v_1=(1,0,1)\\
v_2=(1,2,3)\\
v_3=(2,2,4)$
Obtain $a_1v_1+a_2v_2+a_3v_3\\
=(1,0,1)a_1+(1,2,3)a_2+(2,2,4)a_3$
We can see that $v_1+v_2=(1,0,1)+(1,2,3)=(2,2,4)=v_3$
Now obtain $a_1v_1+a_2v_2+a_3(v_1+v_2)\\=a_1(1,0,1)+a_2(1,2,3)+a_3(2,2,4)$
And $(a_1+a_3)v_1+(a_2+a_3)v_2\\
=(a_1+a_3)(1,0,1)+(a_2+a_3)(1,2,3)$
Hence, the linear span $\{(1,0,1),(1,2,3)\}$ of the resulting set of vectors are the same as the linear span of $\{v_1,v_2,...,v_k\}$
