Answer
True
Work Step by Step
The Laplace Transform can be written as:
$F(s)=\int_{0}^{\infty} e^{-st} f(t) dt $
Since, $F(s)=\int_{0}^{\infty} e^{-st} e^t dt=\dfrac{1}{s-1} $
Therefore, the given statement is $\bf{True}$.
Differential Equations and Linear Algebra (4th Edition)
by Goode, Stephen W.; Annin, Scott A.
Published by
Pearson
ISBN 10:
0-32196-467-5
ISBN 13:
978-0-32196-467-0
Chapter 10 - The Laplace Transform and Some Elementary Applications - 10.1 Definition of the Laplace Transform - True-False Review - Page 675: f
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