## College Algebra 7th Edition

$9$ of each coin.
Let the amount of each coin be $m$. Then, $x+5x+10x$ is the value of the coins, which the problem stated was $144$. Set up the equation $(1+5+10)x=144$. Solving for $x$, $x=\frac{144}{(1+5+10)}=\frac{144}{16}=9$ of each coin.