#### Answer

$2n^{2}+2n+1$

#### Work Step by Step

$n$ = the first integer
$n+1$ = the second integer
Thus the sum of their squares is:
$n^{2}+(n+1)^{2}=n^{2}+(n^{2}+2n+1)=2n^{2}+2n+1$

Published by
Brooks Cole

ISBN 10:
1305115546

ISBN 13:
978-1-30511-554-5

$2n^{2}+2n+1$

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