Answer
See explanation
Work Step by Step
i) $a^2-b^2=(a+b)(a-b)$
ii) $a^2+2ab+b^2=(a+b)^2$
iii)$ a^3+b^3=(a+b)(a^2-ab+b^2)$
Using the first formula, $x^2-3^2=(x+3)(x-3)$
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