Chapter 9, Counting and Probability - Section 9.4 - Expected Value - 9.4 Exercises - Page 680: 10

$\$14.25$

$P(\text{Ace}) = \dfrac{4}{52}=\dfrac{1}{13}$ $P(\text{Face card}) =\dfrac{12}{52}= \dfrac{3}{13}$ $P(\text{8 of clubs}) =\dfrac{1}{52}$ The expected value is: $104\times\dfrac{1}{13} + 26\times\dfrac{3}{13} + 13\times\dfrac{1}{52} = 14.25$ The expected value of $\$14.25$.