College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 9, Counting and Probability - Chapter 9 Review - Exercises - Page 683: 17

Answer

a) 240 b) 3360 c) 1680

Work Step by Step

a) The number of ways to choose a major and minor is $16P2 = 240$. b) The number of ways to choose a major, first minor, and second minor is $16P3 = 3360$. c) The number of ways to choose a major is 16, and the number of ways to choose 2 minors from the remaining subjects is $15P2 = 105$, so in total there are $16 \times 105 = 1680$ ways to choose it.
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